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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
744
744
Part of
2011 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 744
Source:
8/29/2011
Let
a
,
b
a,\ b
a
,
b
be real numbers. If
∫
0
3
(
a
x
−
b
)
2
d
x
≤
3
\int_0^3 (ax-b)^2dx\leq 3
∫
0
3
(
a
x
−
b
)
2
d
x
≤
3
holds, then find the values of
a
,
b
a,\ b
a
,
b
such that
∫
0
3
(
x
−
3
)
(
a
x
−
b
)
d
x
\int_0^3 (x-3)(ax-b)dx
∫
0
3
(
x
−
3
)
(
a
x
−
b
)
d
x
is minimized.
calculus
integration
inequalities
calculus computations