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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
734
734
Part of
2011 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 734
Source: 2011 Saga University entrance exam/Agriculture
7/3/2011
Find the extremum of
f
(
t
)
=
∫
1
t
ln
x
x
+
t
d
x
(
t
>
0
)
f(t)=\int_1^t \frac{\ln x}{x+t}dx\ (t>0)
f
(
t
)
=
∫
1
t
x
+
t
l
n
x
d
x
(
t
>
0
)
.
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