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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
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Part of
2011 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 728
Source: created by kunny
6/28/2011
Evaluate
∫
π
12
π
6
sin
x
−
cos
x
−
x
(
sin
x
+
cos
x
)
+
1
x
2
−
x
(
sin
x
+
cos
x
)
+
sin
x
cos
x
d
x
.
\int_{\frac {\pi}{12}}^{\frac{\pi}{6}} \frac{\sin x-\cos x-x(\sin x+\cos x)+1}{x^2-x(\sin x+\cos x)+\sin x\cos x}\ dx.
∫
12
π
6
π
x
2
−
x
(
sin
x
+
cos
x
)
+
sin
x
cos
x
sin
x
−
cos
x
−
x
(
sin
x
+
cos
x
)
+
1
d
x
.
calculus
integration
trigonometry
logarithms
calculus computations