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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
692
692
Part of
2011 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 692
Source:
4/17/2011
Evaluate
∫
0
π
12
tan
2
x
−
3
3
tan
2
x
−
1
d
x
\int_0^{\frac{\pi}{12}} \frac{\tan ^ 2 x-3}{3\tan ^ 2 x-1}dx
∫
0
12
π
3
t
a
n
2
x
−
1
t
a
n
2
x
−
3
d
x
.created by kunny
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