MathDB
Problems
Contests
National and Regional Contests
Japan Contests
Today's Calculation Of Integral
2011 Today's Calculation Of Integral
681
681
Part of
2011 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 681
Source:
2/18/2011
Evaluate
∫
0
π
2
1
−
2
sin
2
x
+
3
cos
2
x
d
x
.
\int_0^{\frac{\pi}{2}} \sqrt{1-2\sin 2x+3\cos ^ 2 x}\ dx.
∫
0
2
π
1
−
2
sin
2
x
+
3
cos
2
x
d
x
.
2011 University of Occupational and Environmental Health/Medicine entrance exam
calculus
integration
trigonometry
calculus computations