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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
679
679
Part of
2011 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 679
Source:
2/13/2011
Find
∑
k
=
1
3
n
1
∫
0
1
x
(
1
−
x
)
k
d
x
\sum_{k=1}^{3n} \frac{1}{\int_0^1 x(1-x)^k\ dx}
∑
k
=
1
3
n
∫
0
1
x
(
1
−
x
)
k
d
x
1
.2011 Hosei University entrance exam/Design and Enginerring
calculus
integration
calculus computations