MathDB
Problems
Contests
National and Regional Contests
Japan Contests
Today's Calculation Of Integral
2010 Today's Calculation Of Integral
643
643
Part of
2010 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 643
Source:
8/24/2010
Evaluate
∫
0
π
x
1
+
sin
3
x
{
(
3
π
cos
x
+
4
sin
x
)
sin
2
x
+
4
}
d
x
.
\int_0^{\pi} \frac{x}{\sqrt{1+\sin ^ 3 x}}\{(3\pi \cos x+4\sin x)\sin ^ 2 x+4\}dx.
∫
0
π
1
+
sin
3
x
x
{(
3
π
cos
x
+
4
sin
x
)
sin
2
x
+
4
}
d
x
.
Own
calculus
integration
trigonometry
calculus computations