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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
624
624
Part of
2010 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 624
Source:
7/8/2010
Find the continuous function
f
(
x
)
f(x)
f
(
x
)
such that the following equation holds for any real number
x
x
x
.
∫
0
x
sin
t
⋅
f
(
x
−
t
)
d
t
=
f
(
x
)
−
sin
x
.
\int_0^x \sin t \cdot f(x-t)dt=f(x)-\sin x.
∫
0
x
sin
t
⋅
f
(
x
−
t
)
d
t
=
f
(
x
)
−
sin
x
.
1977 Keio University entrance exam/Medicine
calculus
integration
function
trigonometry
real analysis
calculus computations