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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
613
613
Part of
2010 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 613
Source:
6/28/2010
Find the area of the part, in the
x
x
x
-
y
y
y
plane, enclosed by the curve
∣
y
e
2
x
−
6
e
x
−
8
∣
=
−
(
e
x
−
2
)
(
e
x
−
4
)
.
|ye^{2x}-6e^{x}-8|=-(e^{x}-2)(e^{x}-4).
∣
y
e
2
x
−
6
e
x
−
8∣
=
−
(
e
x
−
2
)
(
e
x
−
4
)
.
2010 Tokyo University of Agriculture and Technology entrance exam
calculus
integration
geometry
logarithms
calculus computations