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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
609
609
Part of
2010 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 609
Source:
6/2/2010
Prove that for positive number
t
t
t
, the function
F
(
t
)
=
∫
0
t
sin
x
1
+
x
2
d
x
F(t)=\int_0^t \frac{\sin x}{1+x^2}dx
F
(
t
)
=
∫
0
t
1
+
x
2
s
i
n
x
d
x
always takes positive number.1972 Tokyo University of Education entrance exam
calculus
integration
function
trigonometry
calculus computations