561

Part of 2010 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 561

Source: created by kunny

Evaluate \int_{\minus{}1}^1 \frac{1\plus{}2x^2\plus{}3x^4\plus{}4x^6\plus{}5x^8\plus{}6x^{10}\plus{}7x^{12}}{\sqrt{(1\plus{}x^2)(1\plus{}x^4)(1\plus{}x^6)}}dx.

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