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Today's Calculation Of Integral
2008 Today's Calculation Of Integral
389
389
Part of
2008 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 389
Source: 1985 Osaka City University entrance exam
11/13/2008
Find the values of
t
∈
[
0
,
2
]
t\in{[0,\ 2]}
t
∈
[
0
,
2
]
for which \int_{t\minus{}3}^{2t} 2^{x^2}\ dx is maximal and minimal.
calculus
integration
derivative
calculus computations