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Today's Calculation Of Integral
2008 Today's Calculation Of Integral
371
371
Part of
2008 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 371
Source: created by hibiki
9/2/2008
Calculate
∫
−
1
1
1
(
1
+
e
x
)
(
1
+
x
2
)
d
x
.
\int_{ - 1}^1 {\frac {1}{(1 + e^x)(1 + x^2)} \ dx. }
∫
−
1
1
(
1
+
e
x
)
(
1
+
x
2
)
1
d
x
.
calculus
integration
calculus computations