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365

Part of 2008 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 365

Source: created by kunny

7/20/2008
Let a, b a,\ b be postive constant numbers. Evaluate \int_0^{\frac {\pi}{2}} \frac {a\cos x \minus{} b\sin x}{b\sin x \plus{} a\cos x}\ dx.
calculusintegrationtrigonometrylogarithmscalculus computations