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331

Part of 2008 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 331

Source: 2007 Keio University entrance exam/Medical

6/1/2008
For aāˆˆR a\in\mathbb{R}, find the minimum value of \int_0^{\frac {\pi}{2}} \left|\frac {\sin 2x}{1 \plus{} \sin ^ 2 x} \minus{} a\cos x\right| dx.
calculusintegrationtrigonometrylogarithmscalculus computations