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Today's Calculation Of Integral
2008 Today's Calculation Of Integral
313
313
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2008 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 313
Source: 1958 Kyoto University entrance exam
4/3/2008
Find the area bounded by the graph of y\equal{}\sqrt[3]{x\plus{}\sqrt{x^2\plus{}1}}\plus{}\sqrt[3]{x\minus{}\sqrt{x^2\plus{}1}}, the line x\minus{}y\minus{}1\equal{}0 and the
x
x
x
axis.
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