252

Part of 2007 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 252

Source: 1971 Tokyo University of Foreign Studies entrance exam

Compare \displaystyle f(\theta) \equal{} \int_0^1 (x \plus{} \sin \theta)^2\ dx and \ g(\theta) \equal{} \int_0^1 (x \plus{} \cos \theta)^2\ dx for

0\leqq \theta \leqq 2\pi .

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