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230

Part of 2007 Today's Calculation Of Integral

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Today's calculation of Integral 230

Source: Oita University entrance exam/Engineering 1990

10/4/2007
Prove that \frac {( \minus{} 1)^n}{n!}\int_1^2 (\ln x)^n\ dx \equal{} 2\sum_{k \equal{} 1}^n \frac {( \minus{} \ln 2)^k}{k!} \plus{} 1.
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