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202

Part of 2007 Today's Calculation Of Integral

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Today's calculation of Integral 202

Source: created by kunny

5/15/2007
Let a, ba,\ b are real numbers such that a+b=1a+b=1. Find the minimum value of the following integral. ∫0π(asin⁡x+bsin⁡2x)2 dx\int_{0}^{\pi}(a\sin x+b\sin 2x)^{2}\ dx
calculusintegrationtrigonometryquadraticsinequalitiescalculus computations