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Today's Calculation Of Integral
2007 Today's Calculation Of Integral
173
173
Part of
2007 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 173
Source: Waseda University entrance exam /1999
1/17/2007
Find the function
f
(
x
)
f(x)
f
(
x
)
such that
f
(
x
)
=
cos
(
2
m
x
)
+
∫
0
π
f
(
t
)
∣
cos
t
∣
d
t
f(x)=\cos (2mx)+\int_{0}^{\pi}f(t)|\cos t|\ dt
f
(
x
)
=
cos
(
2
m
x
)
+
∫
0
π
f
(
t
)
∣
cos
t
∣
d
t
for positive inetger
m
.
m.
m
.
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integration
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