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170

Part of 2007 Today's Calculation Of Integral

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Today's calculation of Integral 170

Source: Toyama Medical and Pharmaceutical University entrance exam 1986

1/15/2007
Let a, ba,\ b be constant numbers such that a2≥b.a^{2}\geq b. Find the following definite integrals. (1) I=∫dxx2+2ax+bI=\int \frac{dx}{x^{2}+2ax+b} (2) J=∫dx(x2+2ax+b)2J=\int \frac{dx}{(x^{2}+2ax+b)^{2}}
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