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Today's Calculation Of Integral
2006 Today's Calculation Of Integral
130
130
Part of
2006 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 130
Source: Tokyo university of Science entrance exam 2006
7/26/2006
Find the value of
a
a
a
such that
∫
0
a
1
e
x
+
4
e
−
x
+
5
d
x
=
ln
2
3
.
\int_{0}^{a}\frac{1}{e^{x}+4e^{-x}+5}\ dx=\ln \sqrt[3]{2}.
∫
0
a
e
x
+
4
e
−
x
+
5
1
d
x
=
ln
3
2
.
calculus
integration
logarithms
calculus computations