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Today's Calculation Of Integral
2006 Today's Calculation Of Integral
125
125
Part of
2006 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 125
Source: created by kunny
7/14/2006
Prove the following inequality for
x
≥
0.
x\geq 0.
x
≥
0.
∫
0
x
(
t
−
t
2
)
sin
2004
t
d
t
<
1
2006
\int_{0}^{x}(t-t^{2})\sin^{2004}t\ dt <\frac{1}{2006}
∫
0
x
(
t
−
t
2
)
sin
2004
t
d
t
<
2006
1
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