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Today's Calculation Of Integral
2006 Today's Calculation Of Integral
106
106
Part of
2006 Today's Calculation Of Integral
Problems
(1)
Today's calculation of integral 106
Source:
6/7/2006
Evaluate
∫
0
1
1
−
x
2
1
+
x
2
d
x
1
+
x
4
\int_0^1 \frac{1-x^2}{1+x^2}\frac{dx}{\sqrt{1+x^4}}
∫
0
1
1
+
x
2
1
−
x
2
1
+
x
4
d
x
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