MathDB

91

Part of 2005 Today's Calculation Of Integral

Problems(1)

Today's calculation of integral 91

Source: created by kunny

11/17/2005
Prove the following inequality. ∑n=0∞∫01x4011(1−x2006)n−12006 dx<20062005 \sum_{n=0}^\infty \int_0^1 x^{4011} (1-x^{2006})^\frac{n-1}{2006}\ dx<\frac{2006}{2005}
calculusintegrationcalculus computations