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82

Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 82

Source: 2004 Osaka University of Education Entrance Exam

9/10/2005
Let 0<a<b0<a<b.Prove the following inequaliy. 1b−a∫ab(ln⁡bx)2dx<2\frac{1}{b-a}\int_a^b \left(\ln \frac{b}{x}\right)^2 dx<2
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