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Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 8

Source: created by kunny

5/7/2005
Calculate the following indefinite integrals. [1] ∫x(x2+3)2dx\int x(x^2+3)^2 dx [2] ∫ln⁡(x+2)dx\int \ln (x+2) dx [3] ∫xcos⁡xdx\int x\cos x dx [4] ∫dx(x+2)2dx\int \frac{dx}{(x+2)^2}dx [5] ∫x−1x2−2x+3dx\int \frac{x-1}{x^2-2x+3}dx
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