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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
77
77
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 77
Source: 1969 Gakusyuin University
8/28/2005
Find the area of the part enclosed by the following curve.
x
2
+
2
a
x
y
+
y
2
=
1
(
−
1
<
a
<
1
)
x^2+2axy+y^2=1\ (-1<a<1)
x
2
+
2
a
x
y
+
y
2
=
1
(
−
1
<
a
<
1
)
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