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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
73
73
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's Calculation of Integral 73
Source: 1994 Kyusyu University
7/22/2005
Find the minimum value of
∫
0
π
(
a
sin
x
+
b
sin
2
x
+
c
sin
3
x
−
x
)
2
d
x
\int_0^{\pi} (a\sin x+b\sin 2x+c\sin 3x-x)^2\ dx
∫
0
π
(
a
sin
x
+
b
sin
2
x
+
c
sin
3
x
−
x
)
2
d
x
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