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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
70
70
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's Calculation of Integral 70
Source: 1991 Ryukoku University
7/16/2005
Find the number of root for
∫
0
π
2
e
x
cos
(
x
+
a
)
d
x
=
0
\int_0^{\frac{\pi}{2}} e^x\cos (x+a)\ dx=0
∫
0
2
π
e
x
cos
(
x
+
a
)
d
x
=
0
at
0
≤
a
<
2
π
0\leq a <2\pi
0
≤
a
<
2
π
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