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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
7
7
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 7
Source: created by kunny
5/6/2005
Calculate the following indefinite integrals. [1]
∫
x
(
x
+
1
)
2
d
x
\int \sqrt{x}(\sqrt{x}+1)^2 dx
∫
x
(
x
+
1
)
2
d
x
[2]
∫
(
e
x
+
2
e
x
+
1
−
3
e
x
+
2
)
d
x
\int (e^x+2e^{x+1}-3e^{x+2})dx
∫
(
e
x
+
2
e
x
+
1
−
3
e
x
+
2
)
d
x
[3]
∫
(
sin
2
x
+
cos
x
)
sin
x
d
x
\int (\sin ^2 x+\cos x)\sin x dx
∫
(
sin
2
x
+
cos
x
)
sin
x
d
x
[4]
∫
x
2
−
x
d
x
\int x\sqrt{2-x} dx
∫
x
2
−
x
d
x
[5]
∫
x
ln
x
d
x
\int x\ln x dx
∫
x
ln
x
d
x
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