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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
65
65
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 65
Source: 2005 Nara Medical University
7/11/2005
Let
a
>
0
a>0
a
>
0
. Find the minimum value of
∫
−
1
a
(
1
−
x
a
)
1
+
x
d
x
\int_{-1}^a \left(1-\frac{x}{a}\right)\sqrt{1+x}\ dx
∫
−
1
a
(
1
−
a
x
)
1
+
x
d
x
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