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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
59
59
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's Calculation of Integral 59
Source: created by kunny
6/30/2005
Evaluate
∫
−
π
π
(
cos
2
x
)
(
cos
2
2
x
)
⋯
(
cos
2
2006
x
)
d
x
\int_{-\pi}^{\pi} (\cos2x)(\cos 2^2x)\cdots (\cos 2^{2006}x)dx
∫
−
π
π
(
cos
2
x
)
(
cos
2
2
x
)
⋯
(
cos
2
2006
x
)
d
x
calculus
integration
trigonometry
calculus computations