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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
35
35
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 35
Source: 1986 Tokyo Denki University
6/6/2005
Determine the value of
a
,
b
a,b
a
,
b
for which
∫
0
1
(
1
−
x
−
a
x
−
b
)
2
d
x
\int_0^1 (\sqrt{1-x}-ax-b)^2 dx
∫
0
1
(
1
−
x
−
a
x
−
b
)
2
d
x
is minimized.
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