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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
33
33
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 33
Source: created by kunny
6/3/2005
Evaluate
∫
−
ln
2
0
d
x
cos
2
h
x
⋅
1
−
2
a
tanh
x
+
a
2
(
a
>
0
)
\int_{-\ln 2}^0\ \frac{dx}{\cos ^2 h x \cdot \sqrt{1-2a\tanh x +a^2}}\ (a>0)
∫
−
l
n
2
0
cos
2
h
x
⋅
1
−
2
a
tanh
x
+
a
2
d
x
(
a
>
0
)
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