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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
25
25
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 25
Source: 1967 Kanazawa University
5/26/2005
Let
∣
a
∣
<
π
2
|a|<\frac{\pi}{2}
∣
a
∣
<
2
π
. Evaluate
∫
0
π
2
d
x
{
sin
(
a
+
x
)
+
cos
x
}
2
\int_0^{\frac{\pi}{2}} \frac{dx}{\{\sin (a+x)+\cos x\}^2}
∫
0
2
π
{
sin
(
a
+
x
)
+
cos
x
}
2
d
x
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