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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
24
24
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 24
Source: 2004 Wakayama Medical University
5/24/2005
Find the minimum value of
∫
0
π
(
x
−
y
)
2
(
sin
x
)
∣
cos
x
∣
d
x
\int_0^{\pi} (x-y)^2 (\sin x)|\cos x|dx
∫
0
π
(
x
−
y
)
2
(
sin
x
)
∣
cos
x
∣
d
x
.
calculus
integration
trigonometry
calculus computations