MathDB

23

Part of 2005 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 23

Source: 2004 Fukushima Medical University

5/24/2005
Evaluate lim⁡a→π2−0 ∫0a (cos⁡x)ln⁡(cos⁡x) dx (0≦a<π2)\lim_{a\rightarrow \frac{\pi}{2}-0}\ \int_0^a\ (\cos x)\ln (\cos x)\ dx\ \left(0\leqq a <\frac{\pi}{2}\right)
calculusintegrationlimittrigonometrylogarithmscalculus computations