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Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 2

Source: created by kunny

5/1/2005
Calculate the following indefinite integrals. [1] ∫cos⁡(2x−π3)dx\int \cos \left(2x-\frac{\pi}{3}\right)dx [2]∫dxcos⁡2(3x+4)\int \frac{dx}{\cos ^2 (3x+4)} [3]∫(x−1)x−23dx\int (x-1)\sqrt[3]{x-2}dx [4]∫x⋅3x2+1dx\int x\cdot 3^{x^2+1}dx [5]∫dx1−xdx\int \frac{dx}{\sqrt{1-x}}dx
calculusintegrationtrigonometrylogarithmscalculus computations