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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
19
19
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 19
Source: created by kunny
5/18/2005
Calculate the following indefinite integrals. [1]
∫
tan
3
x
d
x
\int \tan ^ 3 x dx
∫
tan
3
x
d
x
[2]
∫
a
m
x
+
n
d
x
(
a
>
0
,
a
≠
1
,
m
n
≠
0
)
\int a^{mx+n}dx\ (a>0,a\neq 1, mn\neq 0)
∫
a
m
x
+
n
d
x
(
a
>
0
,
a
=
1
,
mn
=
0
)
[3]
∫
cos
5
x
d
x
\int \cos ^ 5 x dx
∫
cos
5
x
d
x
[4]
∫
sin
2
x
cos
3
x
d
x
\int \sin ^ 2 x\cos ^ 3 x dx
∫
sin
2
x
cos
3
x
d
x
[5]
∫
d
x
sin
x
\int \frac{dx}{\sin x}
∫
s
i
n
x
d
x
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