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18

Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 18

Source: created by kunny

5/18/2005
Calculate the following indefinite integrals. [1] ∫(sin⁡x+cos⁡x)4dx\int (\sin x+\cos x)^4 dx [2] ∫e2xex+1dx\int \frac{e^{2x}}{e^x+1}dx [3] ∫sin⁡4xdx\int \sin ^ 4 xdx [4] ∫sin⁡6xcos⁡2xdx\int \sin 6x\cos 2xdx [5] ∫x2(x+1)3dx\int \frac{x^2}{\sqrt{(x+1)^3}}dx
calculusintegrationtrigonometrylogarithmscalculus computations