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16

Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 16

Source: created by kunny

5/16/2005
Calculate the following indefinite integrals. [1] ∫sin⁡(ln⁡x)dx\int \sin (\ln x)dx [2] ∫x+sin⁡2xxsin⁡2xdx\int \frac{x+\sin ^ 2 x}{x\sin ^ 2 x}dx [3] ∫x3x2+1dx\int \frac{x^3}{x^2+1}dx [4] ∫x22x−1dx\int \frac{x^2}{\sqrt{2x-1}}dx [5] ∫x+cos⁡2x+1xcos⁡2xdx\int \frac{x+\cos 2x +1}{x\cos ^ 2 x}dx
calculusintegrationtrigonometrylogarithmscalculus computations