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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
14
14
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 14
Source: created by kunny
5/14/2005
Calculate the following indefinite integrals. [1]
∫
sin
x
cos
x
1
+
sin
2
x
d
x
\int \frac{\sin x\cos x}{1+\sin ^ 2 x}dx
∫
1
+
s
i
n
2
x
s
i
n
x
c
o
s
x
d
x
[2]
∫
x
log
10
x
d
x
\int x\log_{10} x dx
∫
x
lo
g
10
x
d
x
[3]
∫
x
2
x
−
1
d
x
\int \frac{x}{\sqrt{2x-1}}dx
∫
2
x
−
1
x
d
x
[4]
∫
(
x
2
+
1
)
ln
x
d
x
\int (x^2+1)\ln x dx
∫
(
x
2
+
1
)
ln
x
d
x
[5]
∫
e
x
cos
x
d
x
\int e^x\cos x dx
∫
e
x
cos
x
d
x
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