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13

Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 13

Source: created by kunny

5/13/2005
Calculate the following integarls. [1] ∫xcos⁡2xdx\int x\cos ^ 2 x dx [2] ∫x−1(3x−1)2dx\int \frac{x-1}{(3x-1)^2}dx [3] ∫x3(2−x2)4dx\int \frac{x^3}{(2-x^2)^4}dx [4] ∫(14x+12x)dx\int \left({\frac{1}{4\sqrt{x}}+\frac{1}{2x}}\right)dx [5] ∫(ln⁡x)2dx\int (\ln x)^2 dx
calculusintegrationtrigonometrylogarithmscalculus computations