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12

Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 12

Source: created by kunny

5/12/2005
Calculate the following indefinite integrals. [1] ∫dx1+cos⁡x\int \frac{dx}{1+\cos x} [2] ∫xx2−1dx\int x\sqrt{x^2-1}dx [3] ∫a−x2dx  (a>0,a≠1)\int a^{-\frac{x}{2}}dx\ \ (a>0,a\neq 1) [4] ∫sin⁡3x1+cos⁡xdx\int \frac{\sin ^ 3 x}{1+\cos x}dx [5] ∫e4xsin⁡2xdx\int e^{4x}\sin 2x dx
calculusintegrationtrigonometrycalculus computations