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Today's Calculation Of Integral
2005 Today's Calculation Of Integral
11
11
Part of
2005 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 11
Source: created by kunny
5/11/2005
Calculate the following indefinite integrals. [1]
∫
6
x
+
1
3
x
2
+
x
+
4
d
x
\int \frac{6x+1}{\sqrt{3x^2+x+4}}dx
∫
3
x
2
+
x
+
4
6
x
+
1
d
x
[2]
∫
e
x
e
x
+
e
a
−
x
d
x
\int \frac{e^x}{e^x+e^{a-x}}dx
∫
e
x
+
e
a
−
x
e
x
d
x
[3]
∫
(
x
+
1
)
3
x
d
x
\int \frac{(\sqrt{x}+1)^3}{\sqrt{x}}dx
∫
x
(
x
+
1
)
3
d
x
[4]
∫
x
ln
(
x
2
−
1
)
d
x
\int x\ln (x^2-1)dx
∫
x
ln
(
x
2
−
1
)
d
x
[5]
∫
2
(
x
+
2
)
x
2
+
4
x
+
1
d
x
\int \frac{2(x+2)}{x^2+4x+1}dx
∫
x
2
+
4
x
+
1
2
(
x
+
2
)
d
x
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