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10

Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 10

Source: created by kunny

5/9/2005
Calculate the following indefinite integrals. [1] ∫(2x+1)x+2 dx\int (2x+1)\sqrt{x+2}\ dx [2] ∫1+cos⁡xx+sin⁡x dx\int \frac{1+\cos x}{x+\sin x}\ dx [3] ∫sin⁡5xcos⁡3x dx\int \sin ^ 5 x \cos ^ 3 x \ dx [4] ∫(x−3)2x4 dx\int \frac{(x-3)^2}{x^4}\ dx [5] ∫dxtan⁡x dx\int \frac{dx}{\tan x}\ dx
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