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Part of 2005 Today's Calculation Of Integral

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Today's calculation of Integral 1

Source: created by kunny

4/30/2005
Calculate the following indefinite integral. [1] ∫e2x(ex+1)2dx\int \frac{e^{2x}}{(e^x+1)^2}dx [2] ∫sin⁡xcos⁡3xdx\int \sin x\cos 3x dx [3] ∫sin⁡2xsin⁡3xdx\int \sin 2x\sin 3x dx [4] ∫dx4x2−12x+9\int \frac{dx}{4x^2-12x+9} [5] ∫cos⁡4xdx\int \cos ^4 x dx
calculusintegrationtrigonometrylogarithmscalculus computations