Let α1,α2,α3 be three congruent circles that are tangent to each other. A third circle β is tangent to them at points A1,A2,A3 respectively. Let P be a point on β which is different from A1,A2,A3. For i=1,2,3, let Bi be the second intersection point of the line PAi with circle αi. Prove that ΔB1B2B3 is equilateral. geometrytangent circlesEquilateral Triangle