3
Part of 2009 Iran MO (2nd Round)
Problems(2)
Geometric Inequality on Angles - Iran NMO 2009 - Problem 3
Source:
9/20/2010
Let be a triangle and the point is on the segment such that is the interior bisector of . We stretch such that it meets the circumcircle of at . We draw a line from such that it meets the lines at , respectively ( is not between and also is not between ).
Prove that .
inequalitiesgeometrycircumcircletrigonometryangle bisectorgeometry proposedGeometric Inequalities
Cards - Iran NMO 2009 - Problem 6
Source:
9/20/2010
people are sitting around a circle table, orderly (means that the distance between two adjacent persons is equal to others) and cards with numbers to are given to them. Some may have no card and some may have more than card. In each round, one [and only one] can give one of his cards with number to his adjacent person if after and before the round, the locations of the cards with numbers don’t make an acute-angled triangle.
(Card with number means the card with number and card with number means the card with number !)
Suppose that the cards are given to the persons regularly clockwise. (Mean that the number of the cards in the clockwise direction is increasing.)
Prove that the cards can’t be gathered at one person.
topologygeometrycircumcirclecalculusintegrationinvariantcombinatorics proposed